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Forum Post: Resultant Forces in Axially Rotated Model

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Hello, The problem that I am having is that my model at some point shifts off of the AutoPIPE X,Y,Z axis. Here is a picture of a section of my current model: As you can see, the model shifts (lets assume 45 degrees negative to the +Z axis for simplicity reason) off of the autopipe axis at point E06. At E24 (in the bottom right corner) there is a support. If I want to determine the resultant forces normal to the pipe (X' and Z') is there an easy method to do this? Trigonometrically speaking - it would be as simple as: Fx' = Fx / Sin(-45) + Fz / Cos(-45) Fz' = Fx / Cos(-45) + Fz / Sin (-45) But... if I want to do this at odd angles (with both X-Z and X-Y rotation) within a larger scale model with many more nodes at angles that are NOT on the AutoPIPE global X,Y,Z axis - this becomes much more difficult. My concern is during the analysis of supports and important nodes/anchors that the forces that AutoPIPE gives during analysis do NOT correlate to the resultant axial, transverse and vertical (shear) forces at each node once the model has gone off path. Are there any fixes or recreatable methods to analyze this? Thanks in advance, -Greg

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